函数y=sinxcosx+(√3)cos²x-(√3)/2的最小正周期
y=(1/2)sin2x+(√3)(1+cos2x)/2-(√3)/2=(1/2)sin2x+(√3/2)cos2x
=sin2xcos(π/3)+cos2xsin(π/3)=sin(2x+π/3)
故最小正周期T=2π/2=π