1/(x+2)+1/(2x+3)=1/(6x+1)-1/(3x-4)
2x+3+x+2/(x+2)(2x+3)=3x-4-6x-1/(6x+1)(3x-4)
3x+5/(x+2)(2x+3)=-(3x+5)/(6x+1)(3x-4)
(x+2)(2x+3)=-(6x+1)(3x-4)
2x^2+7x+6=-(18x^2-21x-4)
20x^2-14x+2=0
(10x-2)(2x-1)=0
x1=1/5,x2=1/2