解f(x)=√3(sin²x-cos²x)-2sinxcosx
=-√3cos2x-sin2x
=-2[sin2xcosπ/3+cos2xsinπ/3]
=-2sin(2x+π/3)
最小正周期T=2π/2=π
注:用到的公式
Cos2A = Cos²A-Sin²A
Sin2A=2SinA•CosA