解
f(x)=sinx+√3cosx
=2(1/2sinx+√3/2cosx)
=2(cosxcosπ/6+sinxsinπ/6)
=2cos(x-π/6)谢谢=2(cosxcosπ/6+sinxsinπ/6)=2cos(x-π/6)这两步是怎么转换的？用公式cos(a-b)=cosacosb+sinasinb令x=a，b=π/6就可以得到了