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(x-y/x+2y)/(x^2-y^2/x^2+4xy+4y^2)先化简后求值 其中x=-2,y=3
人气:441 ℃ 时间:2020-06-08 04:05:31
解答
(x-y/x+2y)/(x^2-y^2/x^2+4xy+4y^2)
=(x-y/x+2y)/(x-y)(x+y)/(x+2y)^2
=1/(x+y)/(x+2y)
=(x+2y)/(x+y)
代入
=4
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