等号在哪啊?这是方程么?如果要是这一长串式子化简的话,解法如下：首先：给你个公式1/a*(a+1)=1/a-1/(a+1)因此1/(x+1)(x+2)+1/(x+2)(x+3)+...+1/(x+1994)(x+1995)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+...+1/(x+1994)-1/...