>
数学
>
y^2-2y+x^2-6x^2+10=0
求[(-2)^x]^y,
人气:381 ℃ 时间:2020-09-03 07:08:07
解答
y^2-2y+x^2-6x^2+10=0
y^2-2y+1+x^2-6x^2+9=0
(y-1)^2+(x-3)^2=0
y=1 x=3
[(-2)^x]^y=[(-2)^3]^1=-8
推荐
已知,x^2+y^2-6x+2y+10=0,求(x+2y)^2(x-2y)^2-(x-2y)(x^2+4y^2)(x+2y)的值.
计算. (1)(a-2b+3c)2-(a+2b-3c)2; (2)[ab(3−b)−2a(b−1/2b2)](−3a2b3); (3)-2100×0.5100×(-1)2013÷(-1)-5; (4)[(x+2y)(x-2y)+4(x-y)
已知x^2+y^2--6x--2y+10=0,求x+y/x--y
2x+y=4x-y-1/2=10+6x+2y/4
(1)-a3•a4•a+(a2)4+(-a4)2 (2)(-3x2y)2 (-2xy3z)3 (3)(5a2b-3ab-1)(-3a2) (4)6x2-(x-1)(x+2)-2(x-1)(x+3) (5)5m×125m÷252m-1 (6)
he was ___ (too much,much too) worried about his son.请问此处填啥?
一元二次方程kx2-(2k-1)x+k+2=0,当k为何值时,方程有两个不相等的实数根?
怎样让在地震中的房屋不容易倒塌
猜你喜欢
可恶的数学题
将28g KOH溶于水配制成1L 溶液,此KOH溶液的物质的量浓度是( ) A.0.5mol•L-1 B.1mol•L-1 C.2mol•L-1 D.4mol•L-1
in my o____ it is a good plan but hard to carry out
用1,2,3,4,5,6,7,8,9这九个数字写出三个大小相等的分数.(每个数字只允许用一次). 例如:3/6=7/14=29/58.
已知二元一次方程2x-4y=5,用含y的代数式表示x,x=______;当y=-2时,x=________.
I when to Beijing when I was young这句对不
已知ai∈R+,且a1+a2+...ai=1 求证:(a1+1/a1)^2+(a2+1/a2)^2+...+(an+1/an)^2>=(n^2+1)^2/n
高一上学期语文要背的课文
© 2026 79432.Com All Rights Reserved.
电脑版
|
手机版