∵ABCD是矩形∴∠A=∠ABC=90°AD=BC=4√2∵M是AD的中点∴AM=1/2AD=2√2∴BM=√(AB平方+AM平方)=√(16+8)=2√6∵CE⊥BM即∠CMB=∠A=90°∴∠BCE+∠EBC=90°∠ABM+∠EBC=90°∴∠BCE=∠ABM∴△ABM∽△EBC∴BM/BC=AB/CE...