已知数列〔an〕是等差数列,其前n项和为Sn,a3=6,S3=12?(1)求数列〔an〕的通项公式?(2)求1/S1+1/S2+·_数学解答

已知数列〔an〕是等差数列,其前n项和为Sn,a3=6,S3=12?(1)求数列〔an〕的通项公式?(2)求1/S1+1/S2+·...
已知数列〔an〕是等差数列,其前n项和为Sn,a3=6,S3=12?(1)求数列〔an〕的通项公式?(2)求1/S1+1/S2+······+1/Sn的值

人气：270 ℃　时间：2019-12-03 02:53:19

解答

1.
S3=3a3-3d=12,
a3-d=4
d=2
a2=4,a1=2
an=2n
2.
Sn=2n+n(n-1)=n²+n=n(n+1)
1/Sn=1/n-1/(n+1)
1/S1+1/S2+······+1/Sn
=1-1/2+1/2-1/3+1/3-1/4+······+1/n-1/(n+1)
=1-1/(n+1)
=n/(n+1)