sinA=asinC/c sinB=bsinC/c
代入原式得 asinC/c+bsinC/c=√2sinC
得a/c+b/c=√2,即a+b=√2c
又因为a+b+c=√2+1 所以c=1
即AB=c=1
S=0.5absinC=1/6sinC
所以ab=1/3 又因为a+b=√2
c²=a²+b²-2abcosC
1=(a+b)²-2ab-2abcosC=2-2/3-4/3cosC
cosC=1/4
C=arccos1/4