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三角函数恒等变换
sin18°·cos36°
求值,a.1/2 b.1/4
人气:442 ℃ 时间:2020-05-13 01:27:25
解答
sin18°·cos36°
=(sin18°·cos18°·cos36°)/cos18°……分子分母同时除cos18°
=(1/4sin72°)/cos18°
=1/4
选B
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