lim(x->1)[x/(x-1)-1/lnx]=lim(x->1)[(xlnx-(x-1))/(x-1)lnx]=lim(x->1)[(xlnx-x+1)/(xlnx-lnx)]=lim(x->1)[((lnx+1)-1)/(lnx+1)-1/x]←洛必达法则=lim(x->1){lnx/[(xlnx+x-1)/x]}=lim(x->1)[xlnx/(xlnx+x-1)]=lim(x...