连接AD,在四边形ABCD中,∠BAD+∠ADC+∠B+∠C=360°∵AB⊥BC,∴∠B=90°．又∵∠C=128°,∴∠BAD+∠ADC=142°．∵CD∥AF,∴∠CDA=∠DAF．在四边形ADEF中,∠DAF+∠EDA+∠F+∠E=360°,∴∠F+∠E=218°．又∵∠E=8...