> 数学 >
已知(x+y-10)²+√(xy-6)=0求x³y-2x²y²+xy³
人气:276 ℃ 时间:2019-10-19 10:12:16
解答
(x+y-10)²+√(xy-6)=0∴{x+y-10=0xy-6=0即{x+y=10xy=6x³y-2x²y²+xy³=xy(x²-2xy+y²)=xy(x²+2xy+y²-4xy)=xy[(x+y)²-4xy]=6×(10²-4×6)=456
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版