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(-1/2)×(-2)=?(-1又1/2)×(-1又1/3)×(-1又1/4)×(-1又1/5)-(-1又1/6)×(-1又1/7)=?
人气:456 ℃ 时间:2020-06-23 01:41:22
解答
(-1/2)×(-2)=1
(-1又1/2)×(-1又1/3)×(-1又1/4)×(-1又1/5)-(?)(-1又1/6)×(-1又1/7)
=(-3/2)×(-4/3)×(-5/4)×(-6/5)-(-7/6)×(-8/7)
= 3/2× 4/3× 5/4 × 6/5 - 7/6 × 8/7
= 6/2 - 8/6
= 3- 4/3
= 1又3分之2
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