> 数学 >
2005×(1×2/1+2×3/1+3×4/1+···+2003×2004/1+2004×2005/1)=?
人气:262 ℃ 时间:2020-04-13 12:12:50
解答
2005×(1×2/1+2×3/1+3×4/1+···+2003×2004/1+2004×2005/1)
=2005×[(1-2/1)1+(2/1-3/1)+(3/1-4/1)+···+(2003/1-2004/1)+(2004/1-2005/1)]
=2005×(1-2005/1)
=2005×(2005/2004)
=2004不好意思,刚才打反了。。。2005×(1/1×2+1/2×3+1/3×4+···+1/2003×2004+1/2004×2005)=?给你悬赏分哪!也有人这么打的,你把它反过来就行了!2005×(1/1×2+1/2×3+1/3×4+···+1/2003×2004+1/2004×2005)=2005×[(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)···+(1/2003-1/2004)+(1/2004-1/2005)]=2005×(1-1/2005)=2005×(2004/2005)=2004
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版