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帮忙求极限,说明原因
lim(x趋向正无穷)x^n*e^(-ax),(a>0,n为自然数)
人气:286 ℃ 时间:2020-05-19 01:35:19
解答
原式=lim(x->+∞)[x^n*e^(-ax)]
=lim(x->+∞)[x^n/e^(ax)]
=lim(x->+∞)[nx^(n-1)/(ae^(ax))](∞/∞型极限,应用罗比达法则)
=lim(x->+∞)[n(n-1)x^(n-2)/(a²e^(ax))](∞/∞型极限,应用罗比达法则)
.
=lim(x->+∞){n!/[(a^n)(e^(ax))]}(∞/∞型极限,应用罗比达法则)
=n!/(a^n)*lim(x->+∞)[1/e^(ax)]
=n!/(a^n)*0(∵a>0)
=0
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