已知:[(x²+y²)-(x-y)²+2y(x-y)]/4y=1,求4x²-(4x-2)/y²[(x²+y²)-(x-y)²+2y(x-y)]/4y＝[2xy+2y(x-y)] /4y=(4xy-2y²)/4y=(4x-2y)/4=1即2x=y+2,故4x²-(4x-2)/y²...谢谢你哈