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lim(x→1)3次根号x^2-2乘3次根号x+1/(x-1)^2
人气:355 ℃ 时间:2020-06-05 06:56:12
解答
lim{[x^(1/3)]^2-2*x^(1/3)+1}/(x-1)^2(x→1)=lim[(x^2)^(1/3)-2*x^(1/3)+1]/(x-1)^2(x→1)lim{[x^(1/3)]^2-2*[x^(1/3)]+1}/(x-1)^2(x→1)=lim[x^(1/3)-1]^2/(x-1)^2(x→1)=lim{[x^(1/3)-1]/(x-1)}^2(x→1)=lim{1/[x...
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