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lim(x→1)(3次根号下(x) -1)/(根号下(x ) -1)
人气:179 ℃ 时间:2020-06-07 07:15:45
解答
令6次根号x=t,则
lim(x→1)(3次根号下(x) -1)/(根号下(x ) -1)
=lim(t→1)(t^2 -1)/(t^3 -1)
=lim(t→1)(t+1)/(t^2 +t+1)
=(1+1)/(1^2+1+1)=1/2
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