∵AD=AE,AB=AC,∠BAC为公共角∴△BAE≌△CAD∴∠ABE=∠ACD,∴∠DCB=∠EBC延长GF到H,使FH=AF,连接BH.在△BAF,△BHF中,AF=FH,BF为公共边,∠BFA=∠BFH(易证)∴△BAF≌△BHF∴∠BAF=∠BHF,∠ABF=∠HBF=45°∵∠BAF=∠AEB...