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解方程,1×2/x+2×3/x+3×4/x+4+5/x+……+2007+2008/x=2007
人气:289 ℃ 时间:2020-06-13 04:08:10
解答
1×2/x+2×3/x+3×4/x+4×5/x+……+2007×2008/x
=x(1-1/2)+x(1/2-1/3)+x(1/3-1/4)+.+x(1/2007-1/2008)
=x(1-1/2+1/2-1/3+1/3-1/4+.+1/2007-1/2008)
=x(1-1/2008)
=2007x/2008
=2007
所以x=2008拜托,你把式子都抄错了,答案能对吗?最后是2007+2008/x,isn't 2007×2008/x1×2/x+2×3/x+3×4/x+4+5/x+……+2007+2008/x=2/x+6/x+12/x+5/x+6/x+.....+2008/x+(4+5+....+2007)=20/x+(5+6+....+2008)/x+(2007+4)(2007-4+1)/2=20/x+[(2008+5)(2008-5+1)/2]/x+2015022=20/x+2017026/x+2015022=2017046/x+2015022=2007x=-2017046/2013015
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