∫(x+2)/(x²+3x+4) dx=(1/2)∫(2x+3)/(x²+3x+4) dx + (1/2)∫dx/(x²+3x+4)=(1/2)∫d(x²+3x+4)/(x²+3x+4) + (1/2)∫dx/[(x+3/2)²+(√7/2)²]=(1/2)ln|x²+3x+4| + (1/2)/(√7/...