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已知tanα=-1/2,2sin²α+sinα·cosα-3cos²α的值
人气:245 ℃ 时间:2019-08-20 23:08:20
解答
sin^2α+2sinαcosα-3cos^2α
=(sin^2α+2sinαcosα-3cos^2a)/(sin^2α+cos^2α)
=(tan^2α+2tanα-3)/(tan^2α+1)
=(1/4-1-3)/(1/4+1)
=-15/5
=-3
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