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如题:∫(x-1)/(x^2+1)dx
人气:281 ℃ 时间:2020-04-13 02:27:55
解答
∫(x-1)/(x^2+1)dx
=∫x/(x^2+1)dx-∫1/(x^2+1)dx
=1/2∫1/(x^2+1)d(x^2+1)-arctanx
=1/2ln(x^2+1)-arctanx+C
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