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y=(sinx-2)/(cosx+1)的值域
人气:368 ℃ 时间:2020-04-04 22:19:46
解答
y=(sinx-2)/(cosx+1) ycosx+y=sinx-2 ycosx-sinx=-2-y √[y+(-1)]sin(x+θ)=-2-y √(1+y)sin(x+θ)=-2-y sin(x+θ)=(-2-y)/√(1+y) -1≤sin(x+θ)≤1 -1≤(-2-y)/√(1+y)≤1 y≤-3/4 值域:(-∞,-3/4]
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