| sinAsinB |
| cosAcosB |
| sinAsinC |
| cosAcosC |
| sinBsinC |
| cosBcosC |
| sinAsinB |
| sinC |
| sin(A+B) |
| cosC |
即
| sinAsinBcosC |
| sin2C |
| abcosC |
| c2 |
| a2+b2−c2 |
| 2c2 |
| a2+b2 |
| c2 |
故答案为:3.
| a2+b2 |
| c2 |
| sinAsinB |
| cosAcosB |
| sinAsinC |
| cosAcosC |
| sinBsinC |
| cosBcosC |
| sinAsinB |
| sinC |
| sin(A+B) |
| cosC |
| sinAsinBcosC |
| sin2C |
| abcosC |
| c2 |
| a2+b2−c2 |
| 2c2 |
| a2+b2 |
| c2 |