(x+1)(x+3)(x+5)(x+7)-9怎么因式分解啊_数学解答

(x+1)(x+3)(x+5)(x+7)-9怎么因式分解啊

人气：324 ℃　时间：2020-05-27 14:01:05

解答

(x+1)(x+3)(x+5)(x+7)-9=[(x+1)(x+7)][(x+3)(x+5)]-9=(x^2+8x+7)(x^2+8x+15)-9=(x^2+8x+7)[(x^2+8x+7)+8]-9=(x^2+8x+7)^2+8(x^2+8x+7)-9=[(x^2+8x+7)+3][(x^2+8x+7)+5] =(x^2+8x+10)(x^2+8x+12) =(x^2+8x+10)(x+2)(x...