> 数学 >
已知x+y=
1
5
,xy=-
1
2
.求代数式(x+3y-3xy)-2(xy-2x-y)的值.
人气:480 ℃ 时间:2020-01-27 19:20:15
解答
∵x+y=
1
5
,xy=-
1
2

∴(x+3y-3xy)-2(xy-2x-y)
=x+3y-3xy-2xy+4x+2y
=5x+5y-5xy
=5(x+y)-5xy
=5×
1
5
-5×(-
1
2

=3.5.
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