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求和Sn=(a-1)+(a^2-2)+(a^3-3)+…+(a^n-n)?
人气:266 ℃ 时间:2020-04-09 20:00:04
解答
(1/3*5)=(1/3-1/5)/21/(2n+1)(2n+3)=(1/(2n+1)-1/(2n+3))/2所以Sn=(1/3*5)+(1/5*7)+(1/7*9)+...+[1/(2n+1)(2n+3)]=0.5*[1/3-1/5+1/5-1/7+...+1/(2n+1)-1/(2n+3)]=0.5*[1/3-1/(2n+3)]
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