计算:{4x(2xy-3xy的平方)-3x平方y(4x-5y)}÷(-0.5xy)
人气:446 ℃ 时间:2019-10-10 05:51:23
解答
{4x(2xy-3xy的平方)-3x平方y(4x-5y)}÷(-0.5xy)
={4x²y(2-3y)-3x²y(4x-5y)}÷(-0.5xy)
=x²y[8-12y-12x+15y]÷(-0.5xy)
=-2(3y-12x+8)
=24x-6y-16O(∩_∩)O谢谢 但我做出来是=【8x²y-12x²y²+15x²y平方】÷(-0.5xy)=(-4x²y+3x²y²)÷(-0.5xy)=-6xy=8x啊,你做错呢,我也错了{4x(2xy-3xy的平方)-3x平方y(4x-5y)}÷(-0.5xy)=(8x²y-12x²y²-12x³y+15x²y²)÷(-0.5xy)(这一步你少一项)=(8x²y-12x³y+3x²y²)÷(-0.5xy)(这里再不能合并了)=-16x+24x²-6xy(上面我弄掉了一个x)
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