>
数学
>
化简分式:
1
x
2
+3x+2
+
1
x
2
+5x+6
+
1
x
2
+7x+12
.
人气:109 ℃ 时间:2019-10-19 17:41:09
解答
原式=
1
(x+1)(x+2)
+
1
(x+2)(x+3)
+
1
(x+3)(x+4)
=(
1
x+1
-
1
x+2
)+(
1
x+2
-
1
x+3
)+(
1
x+3
-
1
x+4
)
=
1
x+1
-
1
x+4
=
3
x
2
+5x+4
.
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(1/x²+x) +(1/x²+3x+2) +(1/x²+5x+6)+(1/x²+7x+12)
化简分式:1/x2+3x+2+1/x2+5x+6+1/x2+7x+12.
1/(x²+3x+2)+1/(x²+5x+6)+1/(x²+7x+12)=1/(3x) 解方程
1/x²+x+1/x²+3x+2+1/x²+5x+6+1/x²+7x+12,分式方程,
化简分式x²+3x+2分之1+x²+5x+6分之1+x²+7x+12分之1
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