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求由方程ysinx-cos(xy)=0所确定的隐函数y=y(x)的导数dy/dx
人气:314 ℃ 时间:2019-08-18 02:42:17
解答
ysinx=cos(xy)
两边分别求导
y'sinx+ycosx=-sin(xy)(y+xy')
y'=-y(sin(xy)+cosx)/(sinx+xsin(xy))
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