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cos(xy)=x求隐函数的导数dy/dx
人气:430 ℃ 时间:2019-11-03 23:48:11
解答
cos(xy)=x
两边对x求导:-sin(xy)[y+xy']=1
y+xy'=-1/sin(xy)
xy'=-y-(1/sin(xy))
y'=[-y-(1/sin(xy))]/x
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