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化简(tan10度-根号3)*cos10度/sin50度
人气:131 ℃ 时间:2019-10-24 10:33:12
解答
(tan10°-√3)cos10°/sin50°
=(sin10°/cos10°-√3)cos10°/sin50°
=(sin10°-√3cos10°)/sin50°
=2[(1/2)sin10°-(√3/2)cos10°]/sin50°
=2(sin10°cos60°-cos10°sin60°)/sin50°
=2sin(10°-60°)/sin50°
=-2
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