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若a>0,b>0,若(a+1)(b+1)=2,arctana+arctanb=
人气:344 ℃ 时间:2020-09-17 11:47:02
解答
答案是1吧 令x=arctana y=arctanb 所以tanx=a tany=b 代到前面 (tanx+1)(tany+1)=2化简 tanxtany +tanx+tany +1 =2 tanx+tany/(1-tanxtany)=1tan(x+y)=tanx+tany/(1-tanxtany)=1arctana+arctanb=x+y=arctan(...
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