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分式的约分与通分问题
约分 (x²+xy)/(x+y)²
x²-y²/(x²-y²)
通分2xy/(x+y)²与x/x²-y²
x-y/2x+2y与xy/(x+y)²
人气:303 ℃ 时间:2019-11-04 12:39:24
解答
(x²+xy)/(x+y)² 分子提取公因式x=x(x+y)/(x+y)² 分子分母同时除以(x+y)=x/(x+y)x²-y²/(x²-y²)好像题目不对2xy/(x+y)²与x/x²-y² 公因式为(x+y)² (x-y)2x...
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