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f(x)=(x+3)/(x-4)值域Ag(x)=(x^2-9)/(x^2-7x+12)值域B求A,B关系
人气:494 ℃ 时间:2020-06-16 01:09:05
解答
f(x)=(x+3)/(x-4),x≠4
=(x-4+7)(x-4)
=1+7/(x-4)
值域f(x)≠1
g(x)=(x^2-9)/(x^2-7x+12),x≠4,x≠3
=(x+3)/(x-4)
g(x)≠1,g(x)≠-6
所以:A包含B
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