f(x)=(2x^2+2x+1)/(x+1)=(2x^2+4x+2 -2x-2 +1)/(x+1)=[2(x+1)^2 +1 -2(x+1)]/(x+1)=2(x+1) +1/(x+1) -2因为 x>-1,x+1>0由基本不等式,得2(x+1) +1/(x+1)>=2根号下2(x+1)*1/(x+1)=2根号2所以f(x)>=2根号2 -2即最小值为...