函数y=3sin(2x+θ)的单调递增区间不可能是a.[π/6,π/3] b.[-π/6,π/3] c.[π/6,2π/3] d._数学解答

函数y=3sin(2x+θ)的单调递增区间不可能是
a.[π/6,π/3] b.[-π/6,π/3] c.[π/6,2π/3] d.[-π/3,π/3]

人气：417 ℃　时间：2020-06-03 05:28:06

解答

D
接上面的“午后蓝山”,
kπ－π/4-θ/2≤x≤kπ＋π/4-θ/2,这是y=3sin(2x+θ)的单调递增区间,可以看到这个区间长度是π/2,而在D中,区间长度为2π/3,已超出π/2