x = x(t),y = y(t) => dy/dx = y'(t) / x'(t)记 y'(t)/x'(t) = z(t),考虑新的参量函数 x = x(t),z = z(t) 则 dz/dx = z'(t) / x'(t) 即 d²y/dx² = dz/dx = (dz/dt) * (dt/dx) 即证.