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(2+1)(2的二次方+2)(2的三次方+2)……(2的64次方)+1
人气:477 ℃ 时间:2019-10-19 13:03:17
解答
1/(2+1)*(1/(2^2+1)*...*(1/(2^64)+1)
= 1/(2-1) * 1/(2+1)*(1/(2^2+1)*...*(1/(2^64)+1)
= 1/(2^2-1) * (1/(2^2+1)*...*(1/(2^64)+1)
= 1/(2^128-1)
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