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(1)a^3-3a+2
(2)(x+1)(x+2)(x+3)(x+4)-120
人气:131 ℃ 时间:2020-07-02 01:27:04
解答
a^3-3a+2=a^3-a-2a+2=a(a-1)(a+1)-2(a-1)=(a+1)(a-1)(a-2)(x+1)(x+2)(x+3)(x+4)-120 =(x+1)(x+4)*(x+2)(x+3)-120=(x^2+5x+4)(x^2+5x+6)-120=(x^2+5x+5+1)(x^2+5x+5-1)-120=(x^2+5x+5)^2-1-120=(x^2+5x+5)-121=(x^2+5...
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