一:(x²+1)y²-x²-1
二:-49x²+14x-1+y²
人气:295 ℃ 时间:2020-07-03 04:08:39
解答
一:(x²+1)y²-x²-1=x²y²-x²+y²-1=x²(y²-1)+(y²-1)
=(x²-1)(y²-1)=(x+1)(x-1)(y+1)(y-1)
二:-49x²+14x-1+y²
=y²-(49x²-14x+1)=y²-((7x)²-14x+1)
=y²-(7x-1)²
=(y+7x-1)(y-7x+1)
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