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(x-y)²-8(y-x-2)
(x+1)(x+2)(x+3)(x+4)+1
用公式法或提公因式法
人气:438 ℃ 时间:2020-09-27 10:16:47
解答
(x-y)² 8(x-y) 16=(x-y 4)²
(x 1)(x 4)(x 2)(x 3) 1
=(x² 5x 4)(x² 5x 6) 1
=[(x² 5x) 4][(x² 5x) 6] 1
=(x² 5x)² 10(x² 5x) 24 1
=[(x² 5x) 5]²
=(x² 5x 5)²
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