梯形ABCD中,AB平行CD,AB等于4,AD等于10,角C等于45°,角D等于30°则CD的长为多少
人气:412 ℃ 时间:2020-03-22 06:38:56
解答
分别过A,B作DC的垂线,垂足是E,F
∵AD=10,∠D=30°
∴AE=5,DE=5√3
∵AE=BF=5,∠C=45°
∴FC=5
∵EF=AB=4
∴CD=DE+EF+FC=5√3+4+5=5√3+9
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