> 物理 >
已知4sinx^2-cosx^2-6sinx+3cosx=0,求(cos2x-cosx^2)/(1-cotx^2)的值
人气:246 ℃ 时间:2020-09-27 03:01:04
解答
采取计算机求解.
4sinx^2-cosx^2-6sinx+3cosx=0
解得:x=0.42314452712305966176816614995526 (rad)
(cos2x-cosx^2)/(1-cotx^2)
解得:0.0710
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版