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知函数f(x)=sin(2x+π/3)-√3sin²x+sinxcosx+(√3)/2.求(1)f(x)的最小正周期(2)f(x)最大值及
人气:149 ℃ 时间:2020-09-10 05:37:23
解答
f(x)=sin(2x+π/3)-√3sin²x+sinxcosx+(√3)/2=sin(2x+π/3)-√3(1-cos2x)/2+sinxcosx+(√3)/2=sin(2x+π/3)+√3cos2x)/2+sinxcosx=sin2xcosπ/3+cos2xsinπ/3)+√3cos2x)/2+sinxcosx=sin2x+√3cos2x=2...
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