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已知函数f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx求函数f(x)的最小正周期及最值
人气:447 ℃ 时间:2019-08-21 11:55:58
解答
f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcos=sin(x+π/3+x)+sin(x+π/3-x)-√3(1-cos^2x)+sinxcos=sin(x+π/3+x)+sin(π/3)-√3+√3cos^2x+0.5sin2x=sin(2x+π/3)+√3/2-√3+√3cos^2x+0.5sin2x=sin(2x+π/3)-...
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