已知1/a+1/b+1/c=0,a+b+c=根号5+根号2,求a2+b2+c2的值
人气：280 ℃ 时间：2019-11-19 05:35:30
解答
1/a+1/b+1/c=0
两边乘abc
ab+ac+bc=0
a2+b2+c2
=(a+b+c)2-2(ab+bc+ac)
=(√2+√5)2
=7+2√10
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